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Geometry and Trigonometry / Right triangles and trigonometry Difficulty: Hard

In triangle X Y Z , angle Y is a right angle, the measure of angle Z is 33°, and the length of YZ¯ is 26 units. If the area, in square units, of triangle X Y Z can be represented by the expression ktan33°, where k is a constant, what is the value of k ?

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Explanation

The correct answer is 338 . The tangent of an acute angle in a right triangle is the ratio of the length of the leg opposite the angle to the length of the leg adjacent to the angle. In triangle XYZ, it's given that angle Y is a right angle. Thus, XY¯ is the leg opposite of angle Z and YZ¯ is the leg adjacent to angle Z . It follows that tanZ=XYYZ. It's also given that the measure of angle Z is 33° and the length of YZ¯ is 26 units. Substituting 33° for Z and 26 for YZ in the equation tanZ=XYYZ yields tan33°=XY26. Multiplying each side of this equation by 26 yields 26tan33°=XY. Therefore, the length of XY¯ is 26tan33°. The area of a triangle is half the product of the lengths of its legs. Since the length of YZ¯ is 26 and the length of XY¯ is 26tan33°, it follows that the area of triangle XYZ is 122626tan33° square units, or 338tan33° square units. It's given that the area, in square units, of triangle XYZ can be represented by the expression ktan33°, where k is a constant. Therefore, 338 is the value of k .